- #1
xec
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Which one has a greater concentration, 1 molar NaOH or 1 molal NaOH aqueous solution?
for the answer Explain Why!
for the answer Explain Why!
Explain Why 1 Molar NaOH is More Concentrated Than 1 Molal NaOH Aqueous Solution
- Thread starter xec
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- Aqueous Concentration
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SUMMARY
1 Molar (1M) NaOH is more concentrated than 1 Molal (1m) NaOH aqueous solution due to the difference in how molarity and molality are defined. Molarity is based on the volume of the solution, while molality is based on the mass of the solvent. To compare the two, one must calculate the molality of 1M NaOH and the molarity of 1m NaOH, using the density of the solution for accurate conversions. This analysis clarifies the concentration differences between these two units.
PREREQUISITES- Understanding of molarity and molality definitions
- Ability to perform density conversions using density tables
- Basic knowledge of solution preparation
- Familiarity with sodium hydroxide (NaOH) properties
- Calculate the molality of 1M NaOH using its density
- Research the differences between molarity and molality in detail
- Explore the impact of temperature on solution density
- Learn about the preparation of standard solutions in laboratory settings
Chemistry students, laboratory technicians, and anyone involved in solution preparation and concentration calculations.
- #2
symbolipoint
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The question needs some clarity. Do you need emphasis on moles or on mass of the solute? Once you establish this, next you must make reference based on comparable concentration units.
- #3
Borek
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Calculate molality of 1M NaOH and molarity of 1m NaOH, everything should be clear then.
Note that you will need solution density for conversion. This has to be taken from density tables.
Symbolipoint is right in general, but wrong in this particular case
Besides, looks to me like in practice it always works the same.
Note that you will need solution density for conversion. This has to be taken from density tables.
Symbolipoint is right in general, but wrong in this particular case
Besides, looks to me like in practice it always works the same.- #4
symbolipoint
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I forgot to account properly for the fact that the same solute (NaOH) is used in both liquids.
Borek commented:
Borek commented: