Why is one a buffer solution but not the other?

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Solution A is a buffer because it maintains a 1:1 ratio of acetic acid (CH3COOH) to its conjugate base (sodium acetate, CH3COONa) after the reaction with sodium hydroxide (NaOH), allowing it to resist pH changes. In contrast, Solution B has a 2:1 ratio of acetic acid to sodium hydroxide, which does not produce an adequate amount of the conjugate base to function as a buffer. The stoichiometry of the reactions indicates that Solution A has sufficient concentrations of both the weak acid and its conjugate base, while Solution B does not. The discussion emphasizes the importance of understanding stoichiometry and the concept of limiting reagents in determining buffer capacity. Ultimately, the ability of a solution to act as a buffer is contingent on the correct proportions of acid and conjugate base present.
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A1s2s2p said:
Sorry, got confused with the mole ratio, it has ##\frac 1 {200}## moles

OK, now follow with the calculations I asked you to do several times earlier in the thread, repeating myself for nth time will be just waste of time.
 
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