Explain Why 1 Molar NaOH is More Concentrated Than 1 Molal NaOH Aqueous Solution

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Discussion Overview

The discussion revolves around the comparison of concentration between 1 molar (1M) NaOH and 1 molal (1m) NaOH aqueous solutions. Participants explore the definitions and implications of molarity and molality, as well as the necessary calculations to clarify the differences in concentration.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested

Main Points Raised

  • Some participants question whether the emphasis should be on the number of moles or the mass of the solute when comparing concentrations.
  • There is a suggestion to calculate the molality of 1M NaOH and the molarity of 1m NaOH to clarify the comparison, noting that solution density is required for conversion.
  • One participant asserts that while a general principle may apply, there are specific cases where the comparison does not hold, indicating a potential disagreement on the application of these principles.
  • Another participant acknowledges a mistake in accounting for the same solute being used in both solutions, hinting at the complexity of the comparison.

Areas of Agreement / Disagreement

Participants do not reach a consensus, as there are competing views on the interpretation of concentration and the relevance of calculations. The discussion remains unresolved regarding which solution is more concentrated.

Contextual Notes

Limitations include the need for density data for accurate conversions between molarity and molality, as well as the potential for differing interpretations of concentration based on the definitions used.

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Which one has a greater concentration, 1 molar NaOH or 1 molal NaOH aqueous solution?
for the answer Explain Why!
 
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The question needs some clarity. Do you need emphasis on moles or on mass of the solute? Once you establish this, next you must make reference based on comparable concentration units.
 
Calculate molality of 1M NaOH and molarity of 1m NaOH, everything should be clear then.

Note that you will need solution density for conversion. This has to be taken from density tables.

Symbolipoint is right in general, but wrong in this particular case :wink: Besides, looks to me like in practice it always works the same.
 
I forgot to account properly for the fact that the same solute (NaOH) is used in both liquids.

Borek commented:
Symbolipoint is right in general, but wrong in this particular case Besides, looks to me like in practice it always works the same.
 

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