Explaining Mass Moment of Inertia: Izz Different from Ixx and Iyy?

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Discussion Overview

The discussion revolves around the mass moment of inertia (MOI) of a rectangular block, specifically examining why the moments of inertia Izz, Ixx, and Iyy differ when considering a cube. Participants explore the implications of the axes' positions relative to the center of mass (COM) and the application of the parallel axes theorem.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant questions the correctness of the MOI values presented on a referenced webpage, noting that for a cube, Ixx should equal Iyy and Izz.
  • Another participant expresses confusion after calculating the MOI for a rectangular block and finding discrepancies with the online resource.
  • A later reply clarifies that the axes do not pass through the COM for Ixx and Iyy, which may explain the differences in values.
  • One participant asserts that their calculations were correct and that the webpage is also accurate, referencing the parallel axes theorem to justify their results.
  • Another participant emphasizes the importance of using the correct center of mass coordinates (x_c, y_c, z_c) rather than the general axes (X, Y, Z) when calculating MOI.
  • A final post raises a question about the notation used for the MOI about the z1 axis in the referenced article, suggesting it should be easily calculable.

Areas of Agreement / Disagreement

Participants express differing views on the correctness of the MOI values presented in the referenced webpage, with some agreeing on the need to consider the COM's position while others remain skeptical about the calculations. The discussion does not reach a consensus on the accuracy of the webpage's claims.

Contextual Notes

Participants highlight the dependence of MOI calculations on the axes' positions relative to the center of mass, indicating that assumptions about the geometry and axis placement are crucial to the discussion.

Fermat
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Can someone explain something to me ?

I refer you to http://www.engineering.com/content/ContentDisplay?contentId=41005050".

If we consider the rectangular block to be a cube, Then I would expect that we would get the mass moments of inertia all equal, Ixx = Iyy = Izz.
But, in the page I referred you to, if we let a = b = L, then we get Ixx = Iyy, but Izz is different.

Can anyone explain why Izz is different from Ixx and Iyy ?
 
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Good question. Looks wrong to me too.
 
Thanks. Now I don't feel so bad.

Someone had asked me for help in calculatring MOI for a rectangular block.

I did some working and got the Izz format in that page. And posted my working on the forum I was at.

Then I decided to check it out on the web.

Imagine my consternation when I found that web page !

I hope some more people tell me it is wrong <hopes mightily>
 
Gottit!

The x-axis and the y-axis don't pass through the COM of the block, but the z-axis does.

Ixcxc is of the same form as Izz, but Ixx needs the parallel axes theorem giving,

Ixx = Ixcxc + M(L/2)²

which gives,

Ixx = (1/12)Ma² + (1/3)ML²

So, my working was right after all :smile:

Oh, yes. And that web page is also correct.
 
Are you sure you looked at the right fomulas?

You had to observe x_C, y_c,z_c, NOT X,y,Z.

x_c,y_c,z_c ARE equal.

(You are right in your observation abotu x and y not being in the center.)

Be aware that the COM is locationally dependent!
 
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