Explanation for term in formula, QFT

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SUMMARY

The discussion centers on the notation used in equation 2.18 of Mandl & Shaw's Quantum Field Theory (QFT) book, specifically the term \(\delta x_i\) in the Lagrangian summation. Participants clarify that \(\delta x_i\) represents infinitesimal spacings between components in a continuum limit, which is essential for deriving the field Lagrangian from a system of finite oscillators. This notation indicates a summation over distinct cells, with the index \(i\) denoting individual components, and serves as a functional derivative in the context of Lagrangian mechanics.

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Hi

I've got a question about a term in a formula I've found in Mandl&Shaw's QFT book

It's about equation 2.18 on page 31

L(t) = {\sum_i \delta \bf{x}_i {\cal L}_i \ ...

Why is there a delta x_i when summing over all lagrangians for getting the lagrange-function for the whole system?
And what operator is that delta in this particular equation?
The difference between two different points? (wouldn't that rather be \Delta \bf{x} ?)
\delta serves only as functional derivative AFAIK
 
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I don't have Mandl & Shaw, this looks like a derivation of a field Lagrangian from a system of finite oscillators? The continuum limit \delta x_i \rightarrow 0 means you're spacing the components closer and closer together, which means their masses (and thus Lagrangians) must be scaled down as \delta x_i if the mass density is to remain unchanged. There's a nice discussion in the final chapter of Goldstein, I assume a QFT book would not go into much detail about this.

As for the notation, it looks like he's summing over infinitesimals \delta x_i, which is a physicist's way of doing calculus. :rolleyes: It essentially means \int dx \, {\cal L} (x).
 
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Rach3 said:
I don't have Mandl & Shaw, this looks like a derivation of a field Lagrangian from a system of finite oscillators? The continuum limit \delta x_i \rightarrow 0 means you're spacing the components closer and closer together, which means their masses (and thus Lagrangians) must be scaled down as \delta x_i if the mass density is to remain unchanged. There's a nice discussion in the final chapter of Goldstein, I assume a QFT book would not go into much detail about this.

yep, exactly, that's what is described in the book


As for the notation, it looks like he's summing over infinitesimals \delta x_i, which is a physicist's way of doing calculus. :rolleyes: It essentially means \int dx \, {\cal L} (x).

oh, IC now the reason of my wrong understanding. He uses \delta x_i because he wants to show explicitly that he's talking about separate cells (with the index i as one of the arguments of the field operator). On the page before that he declares explicitly his -in my opinion, awkward - notation.

Thanks ;)
 

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