kith
Science Advisor
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Yes. In ordinary QM, the position wavefunction can be written as a superposition of momentum eigenstates. Analogously in QFT, the field operator can be written as a sum of operators which create or annihilate a particle with definite momentum. If we act with the field operator on the vacuum, it creates in effect a particle with definite location.carllacan said:How can both that operator and the creation operator create a particle out of the vacuum state? They seem to be different things. Does the first creates a particle with a definite position and the second a particle with a definite momentum?
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