Exploring Alpha, Beta, Gamma Decay & Conservation of Mass/Energy

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Homework Help Overview

The discussion revolves around alpha and beta decay, focusing on the conservation of mass and energy as described by E=mc^2. Participants explore the implications of kinetic energy in decay processes and the variations in decay energy among different isotopes.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between mass loss and kinetic energy in alpha decay, questioning whether mass is converted into kinetic energy. They also explore how the velocity of alpha particles may vary among isotopes due to size and charge differences.

Discussion Status

Some participants have provided feedback on the original poster's reasoning, while others have clarified misconceptions about beta decay processes. There is an ongoing exploration of the differences in decay energy and the factors influencing it.

Contextual Notes

Participants note the complexity of decay processes, including the distinction between beta plus decay and electron capture, and mention the Geiger–Nuttall law as a relevant concept. There is also an acknowledgment of the varying speeds of beta particles compared to alpha particles.

gbaby370
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I am completing an assignment that is covering alpha, beta, and gamma decay. I am going to try and keep this as general as possible, as I want to figure this out myself but I just looking for feedback to make sure I am on the right track.

I noticed that after alpha decay, the mass of the alpha particle and daughter atom is not quite equal to the parent atom. It wants to know whether I think mass and energy are conserved relative to E=mc^2. I noticed there was roughly 8.0x10^-13 J's less after the reaction. But I did a bit of research on the speed of an alpha particle, converted the mass of the alpha particle to kg, and when I plugged them into the kinetic energy formula (ek=.5mv^2), it gave roughly the difference between the parent vs. daughter alpha particle. That being said, could some of the mass have been converted into kinetic energy of the alpha particle?
 
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Yes! I believe you're right. :approve: Very nice.

The energy release of alpha decay (difference between the rest mass of the initial atom minus the sum of the rest masses of the daughter atom and alpha particle, times c2) is primarily in the form of kinetic energy.

And most of that kinetic energy is in the motion of the alpha particle, particularly if the parent atom was heavy. Due to conservation of momentum, the daughter atom might end up with a small fraction of that kinetic energy, but most of the energy is with the alpha particle. (You can prove this to yourself as an exercise. Using conservation of momentum, find the respective velocities of two objects separating from each other, initially at rest, when one mass is much bigger than the other. Then find the kinetic energy of each object via ½mv2*, and compare. You should find that the less massive object gets more of the energy.)

*(Using the Newtonian K.E. = ½mv2 should approximate this pretty well. The velocity of alpha particles is a pretty small fraction of c.)
 
Thanks!

Is it also safe to say that that velocity of the alpha particle will be different in some isotopes due to the different sizes and charges? (referring to Coulombe's Law)
 
gbaby370 said:
Thanks!

Is it also safe to say that that velocity of the alpha particle will be different in some isotopes due to the different sizes and charges? (referring to Coulombe's Law)
I'm not an expert on this subject, but I'm led to believe that there is surprisingly little variation in the decay energy. (And for the most part, a parent atom has to be pretty heavy in the first place [heavier than maybe nickel?], before it is likely to emit an alpha particle. Meaning that most kinetic energy stays with the alpha particle rather than the daughter atom, for even lighter parent atoms [relatively speaking]. So there's not a whole lot of variation.) I've provide a link below regarding the "Geiger–Nuttall law" that might be informative.

http://en.wikipedia.org/wiki/Geiger%E2%80%93Nuttall_law
 
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Since we're on the subject of decay,

In beta plus decay, and electron is released, but within the daughter atom a proton will fuse with an electron to create a neutron. That being said, the mass of the daughter atom is a bit larger. I'm guessing that what when the proton fuses with the electron, the energy that kept the electron in orbit around the atom was converted to mass along as well? What are your thoughts?
 
gbaby370 said:
Since we're on the subject of decay,

In beta plus decay, and electron is released,
I think you mean a positron (and a neutrino).
but within the daughter atom a proton will fuse with an electron to create a neutron.
don't confuse β+ decay with electron capture decay. β+, β-, and electron capture decays all have similarities, but they are not the same thing.
That being said, the mass of the daughter atom is a bit larger.
Try that one again.

Let me give you an example of a β+ decay:

40K40Ar + e+ + νe

(where νe is a neutrino).

Now compare the masses of the original Potassium atom to that of the Argon atom:

Potassium 40 mass (in unified atomic mass units): 39.963998475 u
Argon 40 mass (in unified atomic mass units): 39.96238312251 u​

(Source WolframAlpha, http://www.wolframalpha.com/)

The difference in that mass energy (ΔE = Δmc2) becomes the mass energies of the positron and neutrino plus their kinetic energies (plus a little involving the recoil of the Argon atom).

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Edit:

And unlike alpha decays, the beta decay energy can vary greatly. Not only that, beta particles normally travel at ultrarelativistic speeds, so you can't use the KE = ½mv2. Instead, you need to use the relativistic version, KE = mc^2(\gamma - 1) where \gamma \equiv \frac{1}{\sqrt{1 - v^2/c^2}}
 
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Interesting, thanks for the info.
 

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