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Homework Statement
[tex]0^{\sqrt{0}}=\sqrt{0^{0}}[/tex]
Is this expression true?
The discussion revolves around the expression \(0^{\sqrt{0}} = \sqrt{0^{0}}\) and its truth value. Participants explore the implications of defining \(0^0\) and the validity of the expression under different interpretations.
The discussion is active, with participants offering various viewpoints on the definitions and assumptions involved. There is no explicit consensus, but meaningful points have been raised regarding the nature of logarithms and the treatment of undefined expressions.
Participants mention assumptions about treating \(0\) as a real number and the implications of using logarithms in their reasoning. There are references to educational experiences that inform their approaches.
?? log(0) is NOT 1. It is, one more time, "undefined".physixguru said:Take logarithm and simplify.
root 0 * log 0 = 0 *1= 0
Assumptions= using root 0= 0 on the basis that zero is a real number.
Taking log to the base 10.
R.H.S.> 1/2*0 * log 0
> 0*1
> 0
Assumptions same as above.
The points raised above by honourable members are very meaningful, this is one of the proof methods i learned at the IIT,delhi.