Exponent Expression Help: Understanding 0^√0 = √0⁰ and Its Truth Value

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Homework Help Overview

The discussion revolves around the expression \(0^{\sqrt{0}} = \sqrt{0^{0}}\) and its truth value. Participants explore the implications of defining \(0^0\) and the validity of the expression under different interpretations.

Discussion Character

  • Conceptual clarification, Assumption checking, Mixed

Approaches and Questions Raised

  • Some participants question the definition of \(0^0\), noting that it can be considered either as 1 or undefined. Others discuss the implications of these definitions on the original expression.

Discussion Status

The discussion is active, with participants offering various viewpoints on the definitions and assumptions involved. There is no explicit consensus, but meaningful points have been raised regarding the nature of logarithms and the treatment of undefined expressions.

Contextual Notes

Participants mention assumptions about treating \(0\) as a real number and the implications of using logarithms in their reasoning. There are references to educational experiences that inform their approaches.

ritwik06
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Homework Statement


[tex]0^{\sqrt{0}}=\sqrt{0^{0}}[/tex]

Is this expression true?
 
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If you consider "undefined = undefined" to be true, then yes.
 


That depends on your view... 0^0 can be defined as 1, or it can be undefined.

See http://en.wikipedia.org/wiki/Exponentiation#Zero_to_the_zero_powerEither way, I think if you define 0^0 as undefined then the expression above does not hold... That would also mean 1/0 = 0^0 which I think doesn't really make sense... I'm not sure on this but I don't think you can say undefined = undefined!
 


Take logarithm and simplify.

root 0 * log 0 = 0 *1= 0

Assumptions= using root 0= 0 on the basis that zero is a real number.
Taking log to the base 10.

R.H.S.> 1/2*0 * log 0
> 0*1
> 0

Assumptions same as above.

The points raised above by honourable members are very meaningful, this is one of the proof methods i learned at the IIT,delhi.
 


physixguru said:
Take logarithm and simplify.

root 0 * log 0 = 0 *1= 0
?? log(0) is NOT 1. It is, one more time, "undefined".
(log(1)= 0, not the other way around.)

Assumptions= using root 0= 0 on the basis that zero is a real number.
Taking log to the base 10.

R.H.S.> 1/2*0 * log 0
> 0*1
> 0

Assumptions same as above.

The points raised above by honourable members are very meaningful, this is one of the proof methods i learned at the IIT,delhi.
 


It was a bad typing error.
 

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