Exponent Expression Help: Understanding 0^√0 = √0⁰ and Its Truth Value

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ritwik06
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Homework Statement


[tex]0^{\sqrt{0}}=\sqrt{0^{0}}[/tex]

Is this expression true?
 
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That depends on your view... 0^0 can be defined as 1, or it can be undefined.

See http://en.wikipedia.org/wiki/Exponentiation#Zero_to_the_zero_powerEither way, I think if you define 0^0 as undefined then the expression above does not hold... That would also mean 1/0 = 0^0 which I think doesn't really make sense... I'm not sure on this but I don't think you can say undefined = undefined!
 


Take logarithm and simplify.

root 0 * log 0 = 0 *1= 0

Assumptions= using root 0= 0 on the basis that zero is a real number.
Taking log to the base 10.

R.H.S.> 1/2*0 * log 0
> 0*1
> 0

Assumptions same as above.

The points raised above by honourable members are very meaningful, this is one of the proof methods i learned at the IIT,delhi.
 


physixguru said:
Take logarithm and simplify.

root 0 * log 0 = 0 *1= 0
?? log(0) is NOT 1. It is, one more time, "undefined".
(log(1)= 0, not the other way around.)

Assumptions= using root 0= 0 on the basis that zero is a real number.
Taking log to the base 10.

R.H.S.> 1/2*0 * log 0
> 0*1
> 0

Assumptions same as above.

The points raised above by honourable members are very meaningful, this is one of the proof methods i learned at the IIT,delhi.
 


It was a bad typing error.