Simplifying Exponent Expression

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SUMMARY

The discussion focuses on simplifying the expression (x^(a-1))/(x^(3a+4)) using properties of exponents. Participants clarify that the expression can be simplified by applying the exponent rule \(\frac{x^m}{x^n} = x^{m-n}\). The correct simplification results in x raised to the power of (a-1) - (3a+4), leading to x^(a-1-3a-4) or x^(-2a-5). Additionally, the distinction between an expression and an equation is emphasized, correcting a common misconception.

PREREQUISITES
  • Understanding of exponent rules, specifically \(\frac{x^m}{x^n} = x^{m-n}\)
  • Familiarity with algebraic manipulation techniques
  • Basic knowledge of mathematical notation and terminology
  • Ability to differentiate between expressions and equations
NEXT STEPS
  • Study properties of exponents in depth
  • Practice simplifying various algebraic expressions
  • Learn about the FOIL method for multiplying binomials
  • Explore common misconceptions in algebraic expressions and equations
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Students learning algebra, educators teaching exponent rules, and anyone looking to improve their mathematical simplification skills.

stonecoldgen
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Homework Statement


simplify:

(x^(a-1))/x^((3a+4))



Homework Equations



i was really dumb to think laws of logarithms would help me, but obviously not...

The Attempt at a Solution



the only thing i know is that the a's can't cancel! i don't know what to do !
 
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Think about the following:

x^a/x^b=(x^a)(x^-b)

Then,

(x^a)(x^-b)=x^[(a)(-b)]

In the problem you presented think FOIL.
 
stonecoldgen said:

Homework Statement


simplify:

(x^(a-1))/x^((3a+4))
Do you mean this?
\frac{x^{a-1}}{x^{3a+4}}
BTW, I don't mean to nitpick, but this is not an equation. It is an expression. Please don't confuse the two.

czelaya said:
Think about the following:

x^a/x^b=(x^a)(x^-b)

Then,

(x^a)(x^-b)=x^[(a)(-b)]

In the problem you presented think FOIL.
If that's an a times negative b at the end, then that is not correct. We need to use one of the properties of exponents, mainly this one:
\frac{x^m}{x^n}=x^{m-n}
 

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