MHB Exponential Func: Solving ln6=ln2+ln3

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The discussion focuses on justifying the equation ln6 = ln2 + ln3 by demonstrating that the exponential function is strictly increasing over the real numbers. This property ensures that the function is invertible, allowing for the simplification of logarithmic expressions. An example is provided with the function f(x) = x^2, which is not strictly increasing and illustrates how non-invertible functions can lead to incorrect conclusions. The importance of the exponential function's behavior is emphasized in validating the equality of logarithms. Understanding this concept is crucial for correctly manipulating logarithmic identities.
Perlita
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Hello everyone,
I was solving this problem:
Justify that ln6= ln2+ln3

So: exp(ln2+ln3)=exp(ln2)*exp(ln3)= 2*3= 6 = exp(ln6)
Till here, my work was okay.
What I didn't understand is : why should we say that the exponential function is strictly increasing over R before being able to simplify the equation and get: ln2+ln3=ln6 ??

Thanks
 
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Perlita said:
Hello everyone,
I was solving this problem:
Justify that ln6= ln2+ln3

So: exp(ln2+ln3)=exp(ln2)*exp(ln3)= 2*3= 6 = exp(ln6)
Till here, my work was okay.
What I didn't understand is : why should we say that the exponential function is strictly increasing over R before being able to simplify the equation and get: ln2+ln3=ln6 ??

Thanks

Hey Perlita! :)

What you need is that the function is invertible.
And a strictly increasing function is invertible.

To illustrate how it can go wrong when the function is not invertible, consider for instance the function given by $f(x)=x^2$.
We have $(-2)^2 = 4 = 2^2$.
But that does not imply that $-2 = 2$.
 
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