Exponents relating to linear equations- help

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To find the equation of the line passing through the points (1, π) and (π₂, π⁴), the gradient was calculated using the formula (y₂ - y₁) / (x₂ - x₁). Initially, confusion arose with the gradient calculation, leading to incorrect results. However, the correct gradient was determined to be m = π₂ - 3. Ultimately, the equation of the line was found to be y = π₂(x), confirming the solution was correct. This highlights the importance of accurately calculating the gradient in linear equations.
cmaro
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So I need to find the equation of the line passing through (1,∏) (∏₂,∏⁴) sorry, the two would only do sub script not super script but does represent squared.

So I had to find the gradient first, so that I could then sub that along with x and y into y=mx+c but I got stuck trying to find the gradient because there is pi4-pi2 / pi2-1.

How do i figure this out? i tried two things and ended up with pi - 1/pi and then pi2-3.. neither of these seem like gradients?
 
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never mind! i figured it out- it was m= pi2-3, and i ended up with an answer of y=pi2(x) which was correct! :)
 

Thread 'Area of Overlapping Squares'

Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?
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