- #1
MorallyObtuse
- 45
- 0
Homework Statement
Express as the product of four factors
Is this correct?
[tex]a^6 - b^6 = (a - b)(a^5 + a^4b + a^3b^2 + a^2b^3 + ab^4 + b^3)[/tex]
What you have written is true. It is not a "correct" response to the problem because, obviously, it does not have four factors. Start again. Think of [itex]a^6- b^6[/itex] as [itex](a^3)^2- (a^3)^2[/itex].MorallyObtuse said:Homework Statement
Express as the product of four factors
Is this correct?
[tex]a^6 - b^6 = (a - b)(a^5 + a^4b + a^3b^2 + a^2b^3 + ab^4 + b^3)[/tex]
1/2" said:Hi MorallyObtuse,
By the law of indices (a m)n=amxn
and so you can also represent it like this(like HallsofIvy said)
=(a^3)^2-(b^3)^2
And then you can simplyfy it like this
=(a^3-b^3)(a^3+b^3)
and finaly u have your 4 terms
(a-b) (a^2+ab+b^2) (a+b)(a^2-ab+b^2)
I think you get it.
MorallyObtuse said:I don't get it?!
Then you should talk to your teacher about it.MorallyObtuse said:No I don't get it
When we express a number as the product of four factors, we are breaking down the number into four smaller numbers that, when multiplied together, equal the original number. This can also be thought of as finding the prime factorization of a number.
Expressing a number as the product of four factors can help us understand the factors and factors of factors that make up a number. This can be useful in many areas of math, such as finding common factors or simplifying fractions.
To find the factors of a number, we can start by listing all of the possible factors and then narrowing down the list by testing each factor to see if it divides evenly into the original number. Another method is to use prime factorization, where we find the prime factors of a number and then combine them to find all of the factors.
Yes, every number can be expressed as the product of four factors. This is because every number can be broken down into prime factors, and we can combine these prime factors to create four factors that equal the original number.
We can use the product of four factors to solve equations by breaking down the numbers in the equation into their prime factors and then rearranging them to find the solution. This can be a useful method for solving equations with large numbers or multiple variables.