Express dV/dt in terms of dr/dt - Derivative Word Problem

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SUMMARY

The discussion focuses on expressing the derivative of the volume of a spherical weather balloon, dV/dt, in terms of the derivative of its radius, dr/dt. The correct formula derived is dV/dt = 4πr²(dr/dt), confirming the relationship between the volume and radius of a sphere. Participants validate the solution and share resources for generating LaTeX scripts, specifically mentioning the use of Texify for efficiency. The conversation emphasizes the importance of understanding derivatives in relation to geometric shapes.

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  • Understanding of calculus, specifically derivatives
  • Familiarity with the formula for the volume of a sphere
  • Basic knowledge of LaTeX for mathematical expressions
  • Experience with mathematical problem-solving techniques
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  • Study the application of the chain rule in calculus
  • Learn more about spherical geometry and its properties
  • Explore advanced LaTeX formatting for mathematical documents
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bobraymund
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Homework Statement



Air is being pumped into a spherical weather balloon. At any time t, the volume of the balloon is V(t) and its radius is r(t).

Express dV/dt in terms of dr/dt.


2. The attempt at a solution

Volume of a Sphere = 4/3 pi r3

I took the derivative of the formula above and got:
3pir2_fracdrdt.gif


I ended up getting:
_LARGE__fracdVdt4pir2_fracdrdt.gif


Did I do this completely wrong? If so, what am I supposed to do?

Thanks,
Bob
 

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  • 3pir2_fracdrdt.gif
    3pir2_fracdrdt.gif
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You're right on the money.

In LaTeX script, your equation looks like this:
\frac{dV}{dt}~=~4\pi r^2 \frac{dr}{dt}

To see the script, click on the expression, and another browser window opens with the LaTeX script.
 
bobraymund said:

Homework Statement



Air is being pumped into a spherical weather balloon. At any time t, the volume of the balloon is V(t) and its radius is r(t).

Express dV/dt in terms of dr/dt.


2. The attempt at a solution

Volume of a Sphere = 4/3 pi r3

I took the derivative of the formula above and got:
3pir2_fracdrdt.gif


I ended up getting:
_LARGE__fracdVdt4pir2_fracdrdt.gif


Did I do this completely wrong? If so, what am I supposed to do?

Thanks,
Bob
I don't see anything at all wrong with it!
 
Thanks guys!

Mark44 said:
In LaTeX script, your equation looks like this:
\frac{dV}{dt}~=~4\pi r^2 \frac{dr}{dt}

To see the script, click on the expression, and another browser window opens with the LaTeX script.

Oh, thanks. I've been using a site called Texify to generate all these pictures! This will save a lot of my time in the future.

Thanks again,
Bob
 

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