Express logarithm in another variable

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SUMMARY

The discussion focuses on expressing the logarithm $\log_{6} 3$ in terms of the variables $m$ and $n$. The key equations provided are $\log_6 3 = m - n + \log_6 2$ and the relationships $\log_6 5 + 1 = m$ and $2\log_6 2 + \log_6 5 = n$. Participants suggest utilizing the equation $\log_6(2 \cdot 3) = 1$ to derive two equations with the unknowns $\log_6 2$ and $\log_6 3$, ultimately leading to a solution in terms of $m$ and $n$.

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songoku
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Homework Statement
Given that ##\log_{6} 30=m## and ##\log_{6} 20=n##, express ##\log_{6} 3## in ##m## or ##n##
Relevant Equations
logarithm property
The best I can get is:

$$\log_{6} 3=m-n+\log_{6} 2$$

Is it possible to get the final answer in terms of ##m## and ##n## only? If yes, I will try to do it again

Thanks
 
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You can make use of the below
\log_63=1-\log_62
\log_65+1=m
2\log_62+\log_65=n
 
Last edited:
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what you did is correct. you need to complete it by using ##\log_6(2\cdot3)=1##, so that you will have two equations with two unknowns (unknowns can be considered to be the ##\log_6 2## and ##\log_6 3##.)
 
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Try adding ##\log_6 3## to both sides.
 
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Thank you very much anuttarasammyak, Delta2, vela
 

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