Expression for Electric Field Outside Sphere

AI Thread Summary
The discussion centers on understanding the electric field outside a sphere using Gauss's law. Participants express confusion over a question that describes a sphere as both uniformly charged and having a variable charge density, which is contradictory. Clarification is sought on the intended meaning of the question. The importance of making an effort to solve the problem before seeking help is emphasized. Overall, the conversation highlights the need for precise language in physics problems.
eric11201120
Messages
1
Reaction score
0
Homework Statement
The charge desnsity within a sphere of radius R is ρ = ρ0 - ar2, where ρ0 and a are constants and r is the distance from the center. Find an expression for a such that the electric field outside the sphere is zero.
Relevant Equations
Electric Field outside a sphere
E = KQ/r2
Electric flux
ΦE=∫EdA
I'm not quite sure where to start. If someone could help me I would very much appreciate it.
 
Physics news on Phys.org
Hint 1: What does Gauss's law tell you?
Hint 2: Given that expression for charge density, what's the total charge within the sphere?
 
  • Like
Likes eric11201120
  • Like
Likes eric11201120
Steve4Physics said:
But there seems to be a mistake in the question. The sphere can't be both 'uniformly charged' and have a charge density which is a function of r.
Yes, a very sloppily worded question!
 
  • Like
Likes eric11201120
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top