Expression for pressure in a brake system - is this correct?

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Homework Help Overview

The discussion revolves around deriving an expression for the force applied to the brake caliper in a hydraulic bicycle braking system. Participants are exploring the relationship between applied forces, moments, and the geometry of the brake lever and pistons, referencing Pascal's law and mechanical advantage.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants are considering the application of Pascal's law and the moments created by forces at different points in the system. Questions are raised about how to incorporate distances related to the lever arms and the relationship between forces at the brake lever and the piston.

Discussion Status

There is an ongoing exploration of the mechanics involved, with some participants suggesting a need for clearer structure in the reasoning. Guidance has been offered to focus on the moments about the pivot and the relationship between the forces applied at different points. Multiple interpretations of the relationships between forces and distances are being discussed.

Contextual Notes

Participants note potential language barriers and uncertainties in terminology, which may affect the clarity of the discussion. There is also a mention of the need to complete the mechanical analysis before addressing the hydraulic aspects of the problem.

dreamliner
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Homework Statement



Write an expression for the force applied to the brake caliper in the braking system(hydraulic) of a bicycle.

F= force applied to the brake lever
a = distance between F and the pivot point of the brake lever.
b= distance between pivot point and lever piston.
d1= diameter of the piston on the brake handle
d2 = diameter of piston on the brake caliper.(PS English is not my mother tongue, so I might have used the wrong words for the different parts of the brake system. I do hope it's possible to understand what I mean.)

Homework Equations



Pascal's law

Force * arm

The Attempt at a Solution



Right away I'm thinking Pascal's law.

My first thought is to write pressure, p, = F1/d1 = F2/d2. I'm a bit unsure about where to incorporate distances a and b.
I'm tempted to use force*arm and write the whole expression as p=(F1*a)/d1 = (F2*b)/d2, but is this correct...?
 
Last edited:
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You are thinking along the right lines, but you need some more structure to it. Let's start with the forces. The force applied is F; what is its moment about the pivot? What is the moment of the force generated at the piston? How are the two related?
 
Well, working on the assumption that moment force is force *length of the arm the force is working on, the amount about the pivot would be the applied force F*the distance a and the moment at the piston would be F*the distance b.
The relation being that the force F is the same in both cases.

But, that's the same as what I wrote in my initial post so I suspect you might be thinking about something else...?
 
Why would the force at the piston equal F?
 
Indeed. I suspect it's a case of hurrying. "Pascal's law uses F/A. I already have a F in the assignment. Great!".

Would it be correct to use F = P*A where P would be the applied force and A would be the surface area of the pistons, and then multiply the results with the distances?
 
Before doing the hydraulic part, finish the mechanics. You have a lever, with given arms, and a given force applied to one arm. Find the force produced at the other arm.
 
dreamliner said:
Well, working on the assumption that moment force is force *length of the arm the force is working on, the amount about the pivot would be the applied force F*the distance a.

So this part is correct?


I might be about to break some major rules of physics here, but I'm pretty much guessing now... Would the force on the piston be the amount about the pivot* distance b?
 

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