MHB Expression involving roots of quadratic equation

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To evaluate the expression $\frac{1}{\alpha^2}+\frac{1}{\beta^2}$ given the roots $\alpha$ and $\beta$ of a quadratic equation, the discussion highlights that this can be rewritten as $\frac{\alpha^2+\beta^2}{\alpha^2\beta^2}$. The sum of the roots is expressed as $-\frac{b}{a}$ and the product as $\frac{c}{a}$. The derived expression ultimately simplifies to $\frac{b^2 - 2ac}{c^2}$. This approach effectively connects the roots of the quadratic equation to the desired expression.
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Given that $\alpha$ and $\beta$ are the roots of a quadratic equation, evaluate $\frac{1}{\alpha^2}+\frac{1}{\beta^2}$.

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I've edited your post to include the problem statement in the body of the post and to give it a meaningful title. Please try to do so on your own in the future. :)

RTCNTC said:
Given that $\alpha$ and $\beta$ are the roots of a quadratic equation, evaluate $\frac{1}{\alpha^2}+\frac{1}{\beta^2}$.
$$\gamma(x-\alpha)(x-\beta)=\gamma x^2-\gamma(\alpha+\beta)x+\gamma\alpha\beta$$

Using $ax^2+bx+c$, the sum of the roots is $-\frac{b}{a}$[/size] and the product of the roots is $\frac{c}{a}$[/size].

The given expression with a common denominator is $\frac{\alpha^2+\beta^2}{\alpha^2\beta^2}$[/size].

That expression evaluates to $\frac{b^2-2ac}{c^2}$[/size].