Expressions for \gamma and \theta in terms of \alpha and \beta?

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Homework Help Overview

The discussion revolves around finding expressions for \(\gamma\) and \(\theta\) in terms of \(\alpha\) and \(\beta\) based on two given expressions for a free particle's wave function. The subject area involves wave mechanics and the manipulation of trigonometric identities.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss replacing variables in the equations and attempt to manipulate the expressions for sine and cosine in terms of exponential functions. There is a focus on grouping like terms and deriving relationships between the variables.

Discussion Status

Some participants have made progress in rewriting the equations and identifying relationships between the variables. However, there is a noted point of confusion regarding the simplification of these relationships, indicating that the discussion is ongoing without a clear resolution yet.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information and methods they can use. There is also a mention of a system issue affecting one participant's ability to proceed.

Slepton
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Homework Statement



For a free particle, i have two expressions.

\varphi(x) = \alphaeikx + \betae-ikx
and


\varphi(x) = \gammasin(kx) + \thetacos(kx)

I have to determine expressions for \gamma and \theta in terms of \alpha and \beta.


Homework Equations



sin(kx) = (eikx - e-ikx)/2i

cos(kx) = (eix + e-ix)/2


The Attempt at a Solution



I replaced sin and cosine in the second equation.
 
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Slepton said:

The Attempt at a Solution



I replaced sin and cosine in the second equation.

That's a good start...what did you end up with?
 
replacing
alpha with A
beta with B
gamma with M
theta with N

I have,

2(Aeikx + Be-ikx) = -Meikx + Me-ikx + Neix + Ne-ix
 
Slepton said:
replacing
alpha with A
beta with B
gamma with M
theta with N

I have,

2(Aeikx + Be-ikx) = -Meikx + Me-ikx + Neix + Ne-ix

Good, now just group like terms together:

2(\alpha e^{ikx}+\beta e^{-ikx})=(\theta-\gamma)e^{ikx}+(\gamma+\theta)e^{-ikx}

Surely you can see where to go from here?
 
actually that's where I'm stuck at. I know its should be something simpler but my system has lasted on me...
 
Surely you can see that 2\alpha=\theta-\gamma and 2\beta=\theta+\gamma...can't you?
 

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