Expressions for \gamma and \theta in terms of \alpha and \beta?

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SUMMARY

The discussion focuses on deriving expressions for \(\gamma\) and \(\theta\) in terms of \(\alpha\) and \(\beta\) for a free particle represented by the wave function \(\varphi(x) = \alpha e^{ikx} + \beta e^{-ikx}\) and \(\varphi(x) = \gamma \sin(kx) + \theta \cos(kx)\). The key equations used are \(\sin(kx) = \frac{e^{ikx} - e^{-ikx}}{2i}\) and \(\cos(kx) = \frac{e^{ikx} + e^{-ikx}}{2}\). The final expressions derived are \(2\alpha = \theta - \gamma\) and \(2\beta = \theta + \gamma\).

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  • Familiarity with Euler's formula for complex exponentials
  • Knowledge of trigonometric identities involving sine and cosine
  • Basic algebraic manipulation skills
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Slepton
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Homework Statement



For a free particle, i have two expressions.

\varphi(x) = \alphaeikx + \betae-ikx
and


\varphi(x) = \gammasin(kx) + \thetacos(kx)

I have to determine expressions for \gamma and \theta in terms of \alpha and \beta.


Homework Equations



sin(kx) = (eikx - e-ikx)/2i

cos(kx) = (eix + e-ix)/2


The Attempt at a Solution



I replaced sin and cosine in the second equation.
 
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Slepton said:

The Attempt at a Solution



I replaced sin and cosine in the second equation.

That's a good start...what did you end up with?
 
replacing
alpha with A
beta with B
gamma with M
theta with N

I have,

2(Aeikx + Be-ikx) = -Meikx + Me-ikx + Neix + Ne-ix
 
Slepton said:
replacing
alpha with A
beta with B
gamma with M
theta with N

I have,

2(Aeikx + Be-ikx) = -Meikx + Me-ikx + Neix + Ne-ix

Good, now just group like terms together:

2(\alpha e^{ikx}+\beta e^{-ikx})=(\theta-\gamma)e^{ikx}+(\gamma+\theta)e^{-ikx}

Surely you can see where to go from here?
 
actually that's where I'm stuck at. I know its should be something simpler but my system has lasted on me...
 
Surely you can see that 2\alpha=\theta-\gamma and 2\beta=\theta+\gamma...can't you?
 

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