I know this is supposed to go in the HW forum but its not working there so i'm trying it here, and i'm actually running into the same problem with another problem AGAIN. Someone tell me if im doing this right:(adsbygoogle = window.adsbygoogle || []).push({});

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[tex]\nabla[/tex]1. The problem statement, all variables and given/known data

Find the extrema of f(x,y)=x-y ; subject to x^{2}-y^{2}=2

2. Relevant equations

[tex]\nabla[/tex]f=[tex]\lambda[/tex][tex]\nabla[/tex]g

3. The attempt at a solution

[tex]\nabla[/tex]f=(1,-1)

[tex]\nabla[/tex]g=(2x, -2x)

(1,-1)=[tex]\lambda[/tex](2x, -2x)

1 = [tex]\lambda[/tex](2x) |-> [tex]\lambda[/tex]=[tex]\frac{1}{2x}[/tex]

-1 = [tex]\lambda[/tex](-2y) |-> [tex]\lambda[/tex]=[tex]\frac{1}{2y}[/tex]

Which means x = y , but it has to satisfy x^{2}-y^{2}=2 and if x=y then it cannot satisfy this meaning there are no extrema for this set of equations.

Am i right??? I tried working it out with other methods but it just keeps not working, however, i plotted the two equations in 3D on Maple and they do intersect so shouldn't there be extrema? Or is the fact that x-y is a plane paralell to the xy-axis mean that all points are extrema?

We never did a problem like this in class, one with no apparent solution, so i'm confused a bit here.

Thanks for the help!

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# Extrema with Lagrange in Vector Calc.

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