Hi guys! Another question on work done that stumbled me.. If I push an object with a constant 3500N force at a constant velocity since the friction is 3500N as well, what is the work done if the displacement is 5m to the right?? At first look, I would say its 3500*5=17500J? Because that's work done against friction right?? Is this even the same as work done on object? However, I'm thinking that it can be 0J too. The reason being that the solution says if I exert 3900N instead, there's a net 400N so 400*5=2000N. This translates to 0J if I exert 3500N instead! Which is right? Or are both right just because the bodies are different? (Is friction in this case considered as a body? I'm treating this question having having only 1 body unless you're saying the floor is another body. If so I'm guessing the work done on the body is 17500N but the work done on the floor is -17500N and the net work done is 0J. HOWEVER, the negative work done is by the object and not by me, although this is the best explanation. What is true??) thanks!!