Extremely easy math, but need expression

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SUMMARY

The discussion centers on calculating a sequence of coordinate points using arithmetic progression. The user describes a method where the first value, X1, is derived by subtracting 30 from a given value, while subsequent values (X2 to X6) are calculated by consistently subtracting 60. The mathematical formula for this sequence is identified as Tn = a + (n-1)d, where 'a' is the first term and 'd' is the common difference, which is 60 in this case. The reference to arithmetic progression confirms the structured nature of the calculations involved.

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Joel DB
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Okay,
This could be the easiest math question on here... but I'm going to ask the dumb question anyway. I have several coordinate points to solve for, and in each case I subtract the same amount from the previous "x" to get the next "x" value (X2...3...4...5...). The only point where I subract a different value is X1. The rest have a constant rate of change (derivative?). Example:

1.) X1 = (some vaule) – 30’
2.) X2 = (X1 – 60’), X3 = (X2 – 60’), X4 = (X3 – 60’), X5 = (X4 – 60’), X6 = (X5 – 60’)

There has to be a simple mathematical formula, other than this sloppy one. Any help would be great.
 
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like Mark44 said this is an arithmetic progression
Here the difference between two terms(of the sequence) is equal
Tn=a+(n-1)d
where a is the first term and d is the difference between two terms(d=T2-T1)
 

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