Factoring a Polynomial with Non-Integer Roots

  • Thread starter Thread starter Chocolaty
  • Start date Start date
  • Tags Tags
    Polynomial
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
3 replies · 3K views
Chocolaty
Messages
48
Reaction score
0
f(t) = t^3 - 6t^2 +9t + 2

f(1) is not equal to 0
f(-1) is not equal to 0
f(2) is not equal to 0
f(-2) is not equal to 0
No common factor, can't group either

How can I work this one out?
thx
 
Physics news on Phys.org
Here's something to remember.
If f=a_0+a_1x+...+a_n x^n is a polynomial with integer coefficients of degree >=1 and q=b/c (ggd(b,c)=1) is a rational root, then b|a_0 and c|a_n.
So the possible rational roots of your polynomial are [itex]\pm 2[/itex], which not roots. This means there are no rational roots so it's a nasty polynomial.
 
I don't believe this is factorable