Factoring algebraic complex expression

Click For Summary
SUMMARY

The discussion focuses on factoring the algebraic expression ac - bd + adi + bci. The initial factorization attempts include isolating the variable 'a' and then factoring out 'b', leading to the expressions a(c + di) - b(d + ci) and a(c + di) - b(d - ci). The participants emphasize the importance of recognizing the similarity between the factors (c + di) and (d - ci), noting that they differ by a factor of i. The conversation concludes with a request for a systematic approach or algorithm for factoring complex expressions.

PREREQUISITES
  • Understanding of complex numbers and their properties
  • Familiarity with algebraic factorization techniques
  • Knowledge of common factors and grouping methods
  • Basic skills in manipulating algebraic expressions
NEXT STEPS
  • Study the properties of complex numbers in algebra
  • Learn advanced factorization techniques for polynomials
  • Explore algorithms for factoring expressions systematically
  • Practice problems involving factoring complex algebraic expressions
USEFUL FOR

Students studying algebra, mathematics educators, and anyone seeking to improve their skills in factoring complex expressions.

Maxo
Messages
160
Reaction score
1

Homework Statement


Factor the expression ac-bd+adi+bci

Homework Equations




The Attempt at a Solution


We can factor the variable 'a' which gives:
a(c+di)-bd+bci
The common factor in the remaining terms is b, and if we also factor out b we get
a(c+di)-b(d+ci)

But this is not the way I want it factorized. I want it to be factored completely. How can that be done step by step?
 
Physics news on Phys.org
Maxo said:
The common factor in the remaining terms is b, and if we also factor out b we get
a(c+di)-b(d-ci)
Do you realize the similarity between the factors (c+di) and (d-ci)? How can you make them the same?
 
Last edited:
Fightfish said:
Do you realize the similarity between the factors (c+di) and (d-ci)? How can you make them the same?
I made a misstake, it should be a(c+di)-b(d-ci). Anyway so you're saying (c+di) and (d-ci) can be made the same. I actually don't see how that could be done? I mean both the real and the imaginary parts of these expressions are different. How are they the same?
 
Maybe I wasn't very clear with what I meant by "make the same", but what I was trying to convey is identifying the common factor between these two terms. Notice that they differ by a factor of i
 
  • Like
Likes 1 person
For your second step, factor out bi instead of just b. Be more careful with signs and brackets.
 
  • Like
Likes 1 person
Now I see it :)

Is there some rule (algorithm) / procedure to follow when factoring like this?
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 14 ·
Replies
14
Views
2K
Replies
1
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 7 ·
Replies
7
Views
4K