How Do You Simplify Complex Algebraic Expressions?

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SUMMARY

The discussion focuses on simplifying the algebraic expression [((1-x)/x) * x^(2/(1-x))] / x^(2x/(1-x)). The key insight provided is the application of the exponent rule x^a/x^b = x^(a-b), where a = 2/(1-x) and b = 2x/(1-x). The final simplified form of the expression is x(1-x), emphasizing the importance of proper parenthesization to avoid misinterpretation.

PREREQUISITES
  • Understanding of algebraic expressions and simplification techniques
  • Familiarity with exponent rules, specifically x^a/x^b = x^(a-b)
  • Knowledge of the importance of parentheses in mathematical expressions
  • Basic skills in manipulating fractions and common factors
NEXT STEPS
  • Study advanced algebraic simplification techniques
  • Learn about exponent rules in greater detail
  • Practice problems involving parenthesization in algebra
  • Explore common algebraic identities and their applications
USEFUL FOR

Students struggling with algebra, educators teaching algebraic concepts, and anyone looking to improve their skills in simplifying complex algebraic expressions.

beaf123
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Homework Statement


I have the expression [((1-x)/x) * x^(2/1-x)] / x^(2x/1-x)

I want to simplify this expression.

Homework Equations


None

The Attempt at a Solution



I am not so good with algebra. But I tried to find a common factor for x^(2/1-x)] / (x^2x)/1-x and then add them. However, it got really ugly so I think I did something wrong. Anyone knows how to simplify this one?[/B]
 
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beaf123 said:

Homework Statement


I have the expression [((1-x)/x) * x^(2/1-x)] / x^(2x/1-x)

I want to simplify this expression.

Homework Equations


None

The Attempt at a Solution



I am not so good with algebra. But I tried to find a common factor for x^(2/1-x)] / (x^2x)/1-x and then add them. However, it got really ugly so I think I did something wrong. Anyone knows how to simplify this one?[/B]

x^a/x^b=x^(a-b). In your case a=2/(1-x) and b=2x/(1-x). Concentrate on simplifying a-b. BTW notice I wrote 2/(1-x) instead of 2/1-x which would be interpreted as (2/1)-x. That's not what I think you mean. Always fully parenthesize expressions!
 
Last edited:
Thanks a lot.

Very smootely my answer becomes x(1-x)
 

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