Factoring Cubic Polynomials/Function

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SUMMARY

The discussion focuses on factoring the cubic polynomial equation t^3 - 6t^2 - 36t - 40 = 0. Participants suggest using the Newton-Raphson method to find initial roots and recommend plotting the function for visual identification of roots. A specific root, -2, is identified, allowing for division of the polynomial by t + 2 to simplify the equation. Additionally, the discussion highlights the importance of testing factors of -40 to discover roots through substitution.

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  • Understanding of cubic polynomials and their properties
  • Familiarity with the Newton-Raphson method for root finding
  • Knowledge of polynomial long division techniques
  • Basic skills in graphing functions to identify roots visually
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Students in mathematics, particularly those studying algebra and calculus, as well as educators looking for effective methods to teach polynomial factoring techniques.

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Homework Statement


Doing my vector mechanics dynamics homework and I cannot believe I am stuck on this part.

trying to factor

t^3 - 6t^2-36t - 40 = 0

Homework Equations




The Attempt at a Solution


I honestly do not remember where to begin. I remember there is a formula for perfect cubes, but do not remember what is needed for this situation. Any tips is greatly appreciated.
 
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There is a formula but it's nasty and you could always just try Newton-Raphson method for the first factor then long division?
 
You can find all the factors of 40 to try guess how the polynomial factors. Generally, though, I find plotting the function is the quickest way of finding its roots, at least for homework problems.
 
Easy way is to find one root and divide the cubic by it.

i.e. in this situation you can see -2 is a root, so divide the polynomial by t+2, then factor the result to get the other roots.
 
If the problem were changed to +36t, then you would be able to factorize by using the perfect cube.
You would end up having (t-6)^3+176=0 and then you could use the sum of two cubes formula to factorize further (or even just solve the equation for t directly).

But this is not the case :smile:
 
Well the simplest way is to find factors of -40. Replace each in the original expression one by one and when the result is zero: Bingo! You've found a root. In this case 10 is one root. next, divide the original expression by x-r (r = root found by trial and error) to get a quadratic equation. solve it and you've got your roots:smile:
 

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