Factoring Cubic Polynomials/Function

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    Cubic Factoring
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Homework Help Overview

The discussion revolves around factoring a cubic polynomial, specifically the equation t^3 - 6t^2 - 36t - 40 = 0, within the context of vector mechanics dynamics homework.

Discussion Character

  • Exploratory, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants discuss various methods for factoring the cubic polynomial, including the use of the Newton-Raphson method, finding roots through trial and error, and considering the implications of changing coefficients in the polynomial.

Discussion Status

There are multiple approaches being explored, including suggestions to find roots by testing factors of -40 and using polynomial long division. Some participants express uncertainty about the initial steps, while others provide potential strategies without reaching a consensus on a single method.

Contextual Notes

Participants note the complexity of the polynomial and the potential for different factoring techniques, as well as the impact of changing the polynomial's coefficients on the factoring process.

CursedAntagonis
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Homework Statement


Doing my vector mechanics dynamics homework and I cannot believe I am stuck on this part.

trying to factor

t^3 - 6t^2-36t - 40 = 0

Homework Equations




The Attempt at a Solution


I honestly do not remember where to begin. I remember there is a formula for perfect cubes, but do not remember what is needed for this situation. Any tips is greatly appreciated.
 
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There is a formula but it's nasty and you could always just try Newton-Raphson method for the first factor then long division?
 
You can find all the factors of 40 to try guess how the polynomial factors. Generally, though, I find plotting the function is the quickest way of finding its roots, at least for homework problems.
 
Easy way is to find one root and divide the cubic by it.

i.e. in this situation you can see -2 is a root, so divide the polynomial by t+2, then factor the result to get the other roots.
 
If the problem were changed to +36t, then you would be able to factorize by using the perfect cube.
You would end up having [itex](t-6)^3+176=0[/itex] and then you could use the sum of two cubes formula to factorize further (or even just solve the equation for t directly).

But this is not the case :smile:
 
Well the simplest way is to find factors of -40. Replace each in the original expression one by one and when the result is zero: Bingo! You've found a root. In this case 10 is one root. next, divide the original expression by x-r (r = root found by trial and error) to get a quadratic equation. solve it and you've got your roots:smile:
 

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