MHB Factoring With Negative Powers

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The discussion focuses on factoring the expression (x^2 + 1)^(-2/3) + (x^2 + 1)^(-5/3). The correct approach involves factoring out the term with the smaller exponent, which is (x^2 + 1)^(-5/3). After factoring, the expression simplifies to (x^2 + 1)^(-5/3)((x^2 + 1) + 1). The final factored form is (x^2 + 1)^(-5/3)(x^2 + 2). The initial selection of the smallest power was noted as incorrect.
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Factor

(x^2 + 1)^(-2/3) + (x^2 + 1)^(-5/3)

Solution:

(x^2 + 1)^(-2/3)[1 + (x^2 + 1)^(2/5)]

Yes?
 
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We are given to factor:

$$\left(x^2+1\right)^{-\frac{2}{3}}+\left(x^2+1\right)^{-\frac{5}{3}}$$

So, we factor out the expression with the smaller exponent, observing that $$-\frac{5}{3}<-\frac{2}{3}$$...and then we subtract that exponent:

$$\left(x^2+1\right)^{-\frac{5}{3}}\left(\left(x^2+1\right)^{-\frac{2}{3}-\left(-\frac{5}{3}\right)}+\left(x^2+1\right)^{-\frac{5}{3}-\left(-\frac{5}{3}\right)}\right)$$

Now, simplify the exponents:

$$\left(x^2+1\right)^{-\frac{5}{3}}\left(\left(x^2+1\right)^{\frac{3}{3}}+\left(x^2+1\right)^{0}\right)$$

$$\left(x^2+1\right)^{-\frac{5}{3}}\left(\left(x^2+1\right)+1\right)$$

$$\left(x^2+1\right)^{-\frac{5}{3}}\left(x^2+2\right)$$
 
I selected the wrong smallest power.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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