MHB Factoring With Negative Powers

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The discussion focuses on factoring the expression (x^2 + 1)^(-2/3) + (x^2 + 1)^(-5/3). The correct approach involves factoring out the term with the smaller exponent, which is (x^2 + 1)^(-5/3). After factoring, the expression simplifies to (x^2 + 1)^(-5/3)((x^2 + 1) + 1). The final factored form is (x^2 + 1)^(-5/3)(x^2 + 2). The initial selection of the smallest power was noted as incorrect.
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Factor

(x^2 + 1)^(-2/3) + (x^2 + 1)^(-5/3)

Solution:

(x^2 + 1)^(-2/3)[1 + (x^2 + 1)^(2/5)]

Yes?
 
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We are given to factor:

$$\left(x^2+1\right)^{-\frac{2}{3}}+\left(x^2+1\right)^{-\frac{5}{3}}$$

So, we factor out the expression with the smaller exponent, observing that $$-\frac{5}{3}<-\frac{2}{3}$$...and then we subtract that exponent:

$$\left(x^2+1\right)^{-\frac{5}{3}}\left(\left(x^2+1\right)^{-\frac{2}{3}-\left(-\frac{5}{3}\right)}+\left(x^2+1\right)^{-\frac{5}{3}-\left(-\frac{5}{3}\right)}\right)$$

Now, simplify the exponents:

$$\left(x^2+1\right)^{-\frac{5}{3}}\left(\left(x^2+1\right)^{\frac{3}{3}}+\left(x^2+1\right)^{0}\right)$$

$$\left(x^2+1\right)^{-\frac{5}{3}}\left(\left(x^2+1\right)+1\right)$$

$$\left(x^2+1\right)^{-\frac{5}{3}}\left(x^2+2\right)$$
 
I selected the wrong smallest power.
 
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