Problem: Let Y1,Y2,...,Yn denote a random sample from the uniform distribution over the interval (0,theta). Show that Y(n)=max(Y1,Y2,...,Yn) is a sufficient statistic for theta by the factorization theorem. Solution: http://www.geocities.com/asdfasdf23135/stat10.JPG 1) While I understand that IA (x)IB (x)=IA intersect B (x), I don't understand the equality circled in red above. In the solutions, they say that I0,theta (y1)...I0,theta (yn)=I0,theta (y(n)). Is this really correct? Shouldn't the right hand side be I0,theta (y(n))I0,infinity (y(1)) ? I believe that the second factor is necessary because the largest observation is greater than zero does not guarantee that the smallest observation is greater than zero. Which one is correct? 2) Also, is I0,theta (y(n)) a function of y(n), a function of theta, or a function of both y(n) and theta? If it is a function of both y(n) and theta, then there is something that I don't understand. Following the definition of indicator function that IA (x) is a function of x alone (it is a function of only the stuff in the parenthesis), shouldn't I0,theta (y(n)) be a function of only y(n) alone? Thank you for explaining! I've been confused with these ideas for at least a week.