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Failing physics in dire need of help. PLEASE!

  1. Nov 19, 2006 #1
    A worker pushes a wheelbarrow with a horizontal force of 50.0N over a level distance of 5.0m. If a frictional force of 43N acts on the wheelbarrow in a direction opposite to that of the worker, what net work is done on the wheelbarrow?

    how would i go about solving this problem?
  2. jcsd
  3. Nov 19, 2006 #2
    The force applied by the worker is constant and along the direction of displacment and the force done by friction is opposite the direction of displacement so we can use the relation

    W = Fd

    The net work is the sum of all the works (watch your signs!).
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