Failing physics in dire need of help. PLEASE

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SUMMARY

The discussion focuses on calculating the net work done on a wheelbarrow when a worker applies a horizontal force of 50.0 N over a distance of 5.0 m, while a frictional force of 43 N opposes the motion. The net work can be determined using the formula W = Fd, where the net force is the difference between the applied force and the frictional force. Therefore, the net work done on the wheelbarrow is calculated as W = (50.0 N - 43 N) * 5.0 m, resulting in a net work of 35.0 J.

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josher1289
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A worker pushes a wheelbarrow with a horizontal force of 50.0N over a level distance of 5.0m. If a frictional force of 43N acts on the wheelbarrow in a direction opposite to that of the worker, what net work is done on the wheelbarrow?

how would i go about solving this problem?
 
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The force applied by the worker is constant and along the direction of displacement and the force done by friction is opposite the direction of displacement so we can use the relation

W = Fd

The net work is the sum of all the works (watch your signs!).
 

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