Failing Physics. Need Dire Help. PLEASE

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The discussion centers on calculating the net work done on a wheelbarrow being pushed by a worker with a force of 50.0 N over a distance of 5.0 m, while facing a frictional force of 43 N. The net work is determined by finding the work done by the worker and subtracting the work done against friction. The formula for work is applied, leading to the conclusion that the net work is the sum of the positive work from the worker and the negative work from friction.

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josher1289
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A worker pushes a wheelbarrow with a horizontal force of 50.0N over a level distance of 5.0m. If a frictional force of 43N acts on the wheelbarrow in a direction opposite to that of the worker, what net work is done on the wheelbarrow?

how would i go about solving this problem?
 
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By looking up the definition of work.
 
josher1289, you'll probably find more help in the homework help section.

Your threads probably going to get moved there soon, just warning you.

Anyway The net work is the total work done on the object(obviously). So find the work done by the person pushing the barrow and the work done by friction and add them up to get the net work. Remember that friction acts in opposition to the motion. What does this mean?
 

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