The problem says A cat falls from a tree, dropping 16 meters to the ground. How long is the cat in the air?(adsbygoogle = window.adsbygoogle || []).push({});

Im not confused with the problem, Im confused with the math..The book gives me of course the gravitational constant of earth and all that. The thing is, earlier it gave me an equation that is used here, which is s=initial velocity(time)+1/2(acceleration)(time) squared (Sorry, Im not sure how to use equations on this thing..). The book says that you would get the answer by using t=square root of 2s/(gravity).

So...I dont understand exactly why it goes fromdistance=1/2(gravity)(time)squaredto the equationtime=square root of 2(s)/(gravity).I understand that you are looking for the time, not the distance, so those two switch out, but what happens to the 1/2 part of this equation? Is it there automatically due to the 2(s)/(gravity) part?

Im sorry if I didnt explain this well enough for anyone to understand what I mean, and if thats the case please tell me and Ill try to clarify...

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# Homework Help: Falling cat - how long is the cat in the air

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