(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A 26.4 cm diameter coil consists of 23 turns of circular copper wire 1.90 mm in diameter. A uniform magnetic field, perpendicular to the plane of the coil, changes at a rate of 8.00E-3 T/s. Determine the current in the loop.

Part Two: Determine the rate at which thermal energy is produced.

2. Relevant equations

EMF=(deltaB*A)/delta T

EMF Total= -N*EMF

I=EMF Total/R

R=(Cu Resistivity*L)/A

L= N*2(Pie)R

A = TR^2

3. The attempt at a solution

EMF= 8E-3*(Pie*.132^2) = 4.379E-4

EMF Total = -23*4.379E-4 = -0.010072

I = -.010072 / ( 1.72E-8 * (23*2*Pie*.123) / (Pie*.95E-3^2) ) = -.093406 A

Part 2:

E THermal=I^2*R = -.093406^2 * .10783 = 9.40E-4 m^2 kg/s^3

Both answers are wrong and I have no idea where I went wrong, and neither do my TAs.

Thanks in advance.

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# Homework Help: Faraday's Law, EMF, Finding Current in Loop

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