Faraday's Law Problem: Calculating Induced EMF in a Loop of Wire

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Homework Help Overview

The problem involves calculating the induced electromotive force (emf) in a loop of wire due to a changing magnetic field. The loop has a specified radius, and the magnetic field is perpendicular to the area enclosed by the wire, which is being reduced to zero over a given time period.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the calculation of magnetic flux and the induced emf, questioning the geometry and the angle used in the calculations. There are attempts to clarify the correct area formula and unit conversions.

Discussion Status

Participants are actively engaging with the problem, correcting each other's misunderstandings about geometry and units. Some guidance has been offered regarding the area calculation and the implications of using the correct radius measurement.

Contextual Notes

There is an emphasis on the importance of units and geometry in the calculations, with some participants expressing frustration over the complexities involved in the problem.

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Homework Statement



Take a loop of wire with a radius of 2.0 cm. A B field is perpendicular to the area enclosed by the wire. If the field is reduced to zero from 0.55 T in 0.25 s, what is the induced emf between the ends of the wire?



Homework Equations


B=Magnetic Field
A=Area
Flux= BA cos(Theta)
EMF = Change in Flux/ Change in time

The Attempt at a Solution



Trying to find Flux but since its perpendicular to the area, cos90 = 0 and this makes no sense. The answer is suppose to be 0.0028V. Any help would be great, Thanks
 
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Your geometry is wrong. You're using the wrong angle.
 
ok my bad its suppose to be cos0 which is 1
with that i found Flux to be = (0.55T)(4pi) which is around 6.9T/m^2
With that 6.9(T/m^2)/0.25(Secs)= 27.6 Volts?
Like i said answer is suppose to be 0.0027V. Is there something wrong or did i just screw up the units some where?
Thanks again...
 
Again the issue is geometry. Look carefully as how you're calculating the area.
 
The area is just( pi)r^2 right?
 
Yes, but be careful what you use for "r".
 
Ohh. I see. its in cm. that should change things abit...Thanks everyone.
 
Success! I have to ask this question: What about physics did you learn from doing this problem?
 
... wat did i learn? I hate physics Tests. =D and UNITS.
 
  • #10
Your answer is more or less correct. My point is that there wasn't much physics in this problem.
 

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