- #1

sdfsfasdfasf

- 67

- 9

- Homework Statement
- I need help deducing whether my textbook is wrong or not.

- Relevant Equations
- E = -N d(phi)dt

Here is a curve of induced emf against time. We know from Faraday's law that E = -N d(phi)dt and due to the negative sign, clearly E and d(phi)/dt must have opposite signs, i.e if E > 0it would not be possible for d(phi)dt > 0, as then -N d(phi)dt = E <0 , when we already defined E >0, clearly a contradiction. You can clearly see that from t=0 to just after t=0.1, E > 0, therefore d(phi)dt < 0. However my solution from the textbook states that initially the flux linkage (N phi) increases, which means that N d(phi)dt >0, which is direct contradiction as clearly E > 0 at the start. Posted the solution down below.