Undergrad Is the Fermi-Dirac distribution equal to zero at the state of highest energy?

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SUMMARY

The Fermi-Dirac distribution, denoted as ##f(\epsilon)##, approaches zero as energy ##\epsilon## increases towards infinity at finite temperatures (##T > 0##). At absolute zero (##T = 0##), the distribution is definitively zero for all energy states greater than the Fermi energy (##\epsilon_\mathrm{F}##). This indicates that states above the Fermi energy are unoccupied, confirming that the highest energy state does not possess any particles at absolute zero.

PREREQUISITES
  • Understanding of Fermi-Dirac statistics
  • Knowledge of Fermi energy (##\epsilon_\mathrm{F}##)
  • Familiarity with concepts of absolute zero temperature (##T = 0##)
  • Basic principles of statistical mechanics
NEXT STEPS
  • Study the implications of Fermi-Dirac distribution in semiconductor physics
  • Explore the behavior of particles at absolute zero temperature
  • Investigate the differences between Fermi-Dirac and Bose-Einstein distributions
  • Learn about the applications of Fermi-Dirac statistics in quantum mechanics
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Physicists, students of quantum mechanics, and anyone interested in statistical mechanics and the behavior of particles at various temperatures.

chikchok
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Fermi-Dirac distribution
I`m sorry if this seems too obvious, just trying to clarify something. When Fermi-Dirac distribution is equal to zero , can we assume it is the state of

the highest energy? (Because the propability of occupation is zero)
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##f(\epsilon)## goes to zero as ##\epsilon \rightarrow \infty## for a finite temperature (##T>0##).

At absolute zero, ##T=0##, then ##f(\epsilon > \epsilon_\mathrm{F}) = 0##, where ##\epsilon_\mathrm{F}## is the Fermi energy.
 

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