- #1
Camille
- 20
- 3
I have a request for some explanation in Feynman diagram concerning repelling/attraction of electrical charges. I have been told that when two charges (say, e1(-) and the e2(-)) repel each other, a photon is being emitted from one of them, and the other charge is later being hit by this photon. There is some confusion I can see in this explanation.
First: Does the charge e1(-) emit just a beam of photons in the direction of charge e2(-)? If yes, then how is that this photons always hit charge e2(-) and never miss? Charge e2(-) could move before photons hit it.
Second: Or perhaps the charge e1(-) emitts photons constantly, in all directions. If that's so, what is the wavelength of those photons? Can we detect them?
Third: Does the interaction between charges is based purely on conservation of momentum? (I mean: charge e1(-) gives up some energy (mass of photon) and is therefore tilted outwards the system and charge e2(-), hit by the photon, also gets tilted - therefore we see the repelling.)
Fourth: In the system of e1(-) and e2(-), do they both emit photons in each other's direction?
First: Does the charge e1(-) emit just a beam of photons in the direction of charge e2(-)? If yes, then how is that this photons always hit charge e2(-) and never miss? Charge e2(-) could move before photons hit it.
Second: Or perhaps the charge e1(-) emitts photons constantly, in all directions. If that's so, what is the wavelength of those photons? Can we detect them?
Third: Does the interaction between charges is based purely on conservation of momentum? (I mean: charge e1(-) gives up some energy (mass of photon) and is therefore tilted outwards the system and charge e2(-), hit by the photon, also gets tilted - therefore we see the repelling.)
Fourth: In the system of e1(-) and e2(-), do they both emit photons in each other's direction?
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