I Feynman Lectures Question on Figure 26-2: "It appears that action is not equal to reaction"

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Feynman's discussion in Lecture 26-2 highlights that action is not equal to reaction when two charged particles move at right angles, leading to an imbalance in forces and a change in net momentum. While the momentum of the particles is not conserved individually, the total momentum of the system, including the electromagnetic field, remains conserved. The fourth Maxwell's equation indicates that a changing electric field contributes to the magnetic field, which is essential for reconciling the apparent discrepancy in action and reaction. By considering both particle and field momentum, the forces can be balanced within the entire system rather than just among the charges. This nuanced understanding emphasizes the importance of including field dynamics in discussions of momentum conservation.
bob012345
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In his lecture 26 vol 2 Feynman discusses charges moving at right angles shown in fig 26-2. As Feynman states "It appears that action is not equal to reaction." He states it will be discussed further but I cannot find that. My question is what is the most updated thought on this 60 year old question? Thanks.
 
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Feynman said:
We will mention two further examples of momentum in the electromagnetic field. We pointed out in Section 26–2 the failure of the law of action and reaction when two charged particles were moving on orthogonal trajectories. The forces on the two particles don’t balance out, so the action and reaction are not equal; therefore the net momentum of the matter must be changing. It is not conserved. But the momentum in the field is also changing in such a situation. If you work out the amount of momentum given by the Poynting vector, it is not constant. However, the change of the particle momenta is just made up by the field momentum, so the total momentum of particles plus field is conserved.
 
Thanks. I thought it might be that similar to the Feynman Disk. Anyone have any other thoughts?
 
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The fourth Maxwell’s equation states that a magnetic field is produced by a current density and by a changing electric field.
Here the changing electric field generates the component of the magnetic field which is not mentioned. After including it the action will be equal to the reaction.
 
Gavran said:
After including it the action will be equal to the reaction.

So what about momentum of the field?
 
Gavran said:
The fourth Maxwell’s equation states that a magnetic field is produced by a current density and by a changing electric field.
Here the changing electric field generates the component of the magnetic field which is not mentioned. After including it the action will be equal to the reaction.
If I understand Feynman’s argument, momentum is conserved by including the field momentum and change in the field momentum balances the forces but the forces do not balance among the charges only but the system of charges and fields.
 
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Sorry for wrong explanation in the post #4.
 
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