Feynman Lectures Question on Figure 26-2: "It appears that action is not equal to reaction"

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Discussion Overview

The discussion centers around a question raised by Feynman regarding the apparent discrepancy between action and reaction in the context of charged particles moving at right angles, as illustrated in Figure 26-2 of his lectures. Participants explore the implications of this observation on momentum conservation within electromagnetic fields.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant inquires about the current understanding of Feynman's statement that "action is not equal to reaction" in the context of charged particles moving orthogonally.
  • Another participant references Section 27-6, explaining that the forces on two charged particles do not balance, leading to a change in net momentum, which is not conserved unless the momentum of the electromagnetic field is also considered.
  • Some participants suggest that the situation may be analogous to the Feynman Disk, indicating a search for similar examples or analogies.
  • One participant discusses the implications of the fourth Maxwell's equation, asserting that including the contribution of a changing electric field leads to a situation where action equals reaction when considering the system of charges and fields together.
  • Another participant reiterates that the action will be equal to the reaction when the field momentum is included, emphasizing the need to consider the entire system rather than just the charges.
  • A later reply acknowledges a previous error in explanation, indicating ongoing refinement of ideas within the discussion.

Areas of Agreement / Disagreement

Participants express differing views on the implications of Feynman's statement, with some agreeing that including field momentum resolves the issue of action and reaction, while others remain uncertain about the completeness of this explanation. The discussion does not reach a consensus.

Contextual Notes

Participants note the complexity of momentum conservation in electromagnetic fields and the necessity of considering both particle and field contributions, but do not resolve the underlying assumptions or implications of these points.

bob012345
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In his lecture 26 vol 2 Feynman discusses charges moving at right angles shown in fig 26-2. As Feynman states "It appears that action is not equal to reaction." He states it will be discussed further but I cannot find that. My question is what is the most updated thought on this 60 year old question? Thanks.
 
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Check out 27-6
Feynman said:
We will mention two further examples of momentum in the electromagnetic field. We pointed out in Section 26–2 the failure of the law of action and reaction when two charged particles were moving on orthogonal trajectories. The forces on the two particles don’t balance out, so the action and reaction are not equal; therefore the net momentum of the matter must be changing. It is not conserved. But the momentum in the field is also changing in such a situation. If you work out the amount of momentum given by the Poynting vector, it is not constant. However, the change of the particle momenta is just made up by the field momentum, so the total momentum of particles plus field is conserved.
 
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Thanks. I thought it might be that similar to the Feynman Disk. Anyone have any other thoughts?
 
Last edited:
The fourth Maxwell’s equation states that a magnetic field is produced by a current density and by a changing electric field.
Here the changing electric field generates the component of the magnetic field which is not mentioned. After including it the action will be equal to the reaction.
 
Gavran said:
After including it the action will be equal to the reaction.

So what about momentum of the field?
 
Gavran said:
The fourth Maxwell’s equation states that a magnetic field is produced by a current density and by a changing electric field.
Here the changing electric field generates the component of the magnetic field which is not mentioned. After including it the action will be equal to the reaction.
If I understand Feynman’s argument, momentum is conserved by including the field momentum and change in the field momentum balances the forces but the forces do not balance among the charges only but the system of charges and fields.
 
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Sorry for wrong explanation in the post #4.
 
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