I'd be extremely grateful if anyone could help me with this ... its mainly part iv) that I'm stuck on but the other parts build up to it! Thanks very much! 1. The problem statement, all variables and given/known data I have a wheel shaped space station of radius 100m rotating about its symmetry axis (defined to be the z axis) at angular velocity w in order to create artificial gravity. i) how fast does the space station have to rotate in order for artificial gravity at the rim to be the same as that on earth (10m/s^2) ii) show that the equations of motion for a free particle in a co-ordinate system fixed to the space station are : x'' = 2wy' + w^2 x y'' = -2wx' + w^2y z'' = 0 ('' denotes second derivate wrt time, ' denotes first derivative) iii) show that by defining the variable u = x + iy the solution is u = (a + bt) e^(-iwt) iv) there is a shower in the space station of height 2m from the floor. Ignoring the initial velocity as it flows out of the shower how long does it take the water to reach the floor? How much is the water displaced horizontally when it reaches the floor? 2. Relevant equations Coriolis force = -2w x v Centrifugal force = -wxwxr 3. The attempt at a solution i) I just equated w^2 r to 10 and solved to get w = 0.316 rad/s ii) and iii) Managed to get these fine iv) I'm not really sure whether I am supposed to use part 3 or not here... To get the time I just used s = 0.5gt^2 where g = 10 and then solved to get t = 0.632 s To get the horizontal distance I just used that the horizontal force is 2wy'. I then subbed in y ' = gt and integrated twice to get x = (wgt^3)/3. subbing in for t and w I then got horizontal displacement is 26.6cm I feel like I have made too many approximations and should have used part 3?