Final Pressure in 5L & 10L Tanks: PV = nRT

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SUMMARY

The final pressure in a 5-liter tank at 911.925 kPa and a 10-liter tank at 4560 torr, when equilibrium is established, can be calculated using the weighted average method. This approach utilizes the formula PV = nRT, where the weights are determined by the respective volumes of the tanks. The final pressure is derived from the initial pressures and volumes, ensuring accurate equilibrium calculations at constant temperature.

PREREQUISITES
  • Understanding of the Ideal Gas Law (PV = nRT)
  • Knowledge of pressure units (kPa and torr)
  • Familiarity with weighted averages in mathematical calculations
  • Basic concepts of gas behavior and equilibrium
NEXT STEPS
  • Research the conversion between pressure units, specifically kPa to atmospheres.
  • Learn about gas laws and their applications in real-world scenarios.
  • Explore advanced topics in thermodynamics related to gas mixtures.
  • Study the implications of volume changes on gas pressure in closed systems.
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Students in chemistry or physics, engineers working with gas systems, and anyone interested in thermodynamic principles and gas behavior in varying conditions.

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1. The valve between a 5 liter tank in which the gas pressure is 911.925 kPa and a 10 liter tank containing gas at 4560 torr is turned open and equilibrium is established at constant temperature. What is the final pressure in the two tanks in atmospheres?



2. PV = nRT



The Attempt at a Solution

 
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This is solved using weighted averages. The final pressure in the 2 tanks is the weighted average of the initial pressure. The weights come from the volumes: V1/(V1+V2) for tank 1, V2/(V1+V2) for tank 2.
 

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