- #1

ptownbro

- 60

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## Homework Statement

The Volume goes from 2.00 Liters to 7.00 Liters, the temperature changes from 800 kelvin to 150 kelvin, and the number moles of gas is quadrupled on a gas sample initially at 1.20 atm. What is the new pressure?

## Homework Equations

PV = nRT, where P = pressure, V = volume, n = moles, R = a given number at 0.0821, and T = temperature.

## The Attempt at a Solution

We assumed that since moles was used here, we need to use the "PV = nRT" version of the ideal gas equation versus the "P

_{1}V

_{1}/ T

_{1}= P

_{2}V

_{2}/ T

_{2}" version. Given that, we also assumed we'd have to apply the factor of the changes in each applicable variable.

Volume factor = 7 / 2 = 3.5

Temperature factor = 150 / 800 = 0.1875

Moles factor = 4

Therefore, mathematically, logic stands you can apply the product of those factors to the given starting pressure amount of 1.20 atm to get the new pressure amount.

PV = nRT

P = nRT / V

P = [ (4 n) x (0.0821) x (0.1875 T) ] / (3.5 V)

P = [ (4 x 0.0821 x 0.1875) / 3.5 ] x (nT / V)

P = 0.0176 nT / V

Your factor is therefore 0.0176 which can be applied to the original pressure to get your new pressure.

Answer:

P = 1.2 atm x 0.0176

P = 0.0211 atm

Can you please confirm if our logic and answer is correct and if not where we went wrong?

Thanks!