Gas Laws - What is the final pressure in the system?

Priyadarshini
Messages
191
Reaction score
4

Homework Statement


Two glass vessels M and N are connected by a closed valve.
M contains helium at 20 °C at a pressure of 1 × 10^5 Pa. N has been evacuated, and has three times the volume of M. In an experiment, the valve is opened and the temperature of the whole apparatus is raised to 100 °C.
What is the final pressure in the system?
A 3.18 × 10^4 Pa
B 4.24 × 10^4 Pa
C 1.25 × 10^5 Pa
D 5.09 × 10^5 Pa

Homework Equations


PV=nRT
Where R=8.31J/Kmol

The Attempt at a Solution


For M
T=20 °C = 298 K
P= 10^5 Pa
V= x
For N
V =3x
T =100°C = 373K
Now do I find the change in the T and V and use PV=nRT to calculate the change in the P and then find the final P? But I do not know the mass of helium, so I can not find the number of moles.
 
on Phys.org
Priyadarshini said:

Homework Statement


Two glass vessels M and N are connected by a closed valve.
M contains helium at 20 °C at a pressure of 1 × 10^5 Pa. N has been evacuated, and has three times the volume of M. In an experiment, the valve is opened and the temperature of the whole apparatus is raised to 100 °C.
What is the final pressure in the system?
A 3.18 × 10^4 Pa
B 4.24 × 10^4 Pa
C 1.25 × 10^5 Pa
D 5.09 × 10^5 Pa

Homework Equations


PV=nRT
Where R=8.31J/Kmol

The Attempt at a Solution


For M
T=20 °C = 298 K
P= 10^5 Pa
V= x
For N
V =3x
T =100°C = 373K
Now do I find the change in the T and V and use PV=nRT to calculate the change in the P and then find the final P? But I do not know the mass of helium, so I can not find the number of moles.
You'll have to work out the mass of the helium given the initial conditions and the fact that vessel M has a fixed volume, VM. The mass will be in terms of VM. You are given the volume of vessel N, VN, in terms of VM.
 
Try to express the number of moles of helium in terms of V (initial volume) and see, if it doesn't cancel out in the final formula.
 
SteamKing said:
You'll have to work out the mass of the helium given the initial conditions and the fact that vessel M has a fixed volume, VM. The mass will be in terms of VM. You are given the volume of vessel N, VN, in terms of VM.
What is the relation between mass and volume? Mass remains constant, irrespective of the gas, but how do I find the mass in terms of Vm?
 
Borek said:
Try to express the number of moles of helium in terms of V (initial volume) and see, if it doesn't cancel out in the final formula.
But I don't know the mass. What is the relation between mass and volume?
 
Priyadarshini said:
What is the relation between mass and volume? Mass remains constant, irrespective of the gas, but how do I find the mass in terms of Vm?
That's what the gas law is telling you: PV = n RT, or n / V = P / RT
 
Priyadarshini said:
But I don't know the mass.

You don't need mass, number of moles is enough. But actually you don't need it either, as in the end it should cancel out, and you should be able to express the final result using given information.

What is the relation between mass and volume?

Once you know number of moles and gas identity, calculating mass is trivial. What is molar mass of helium?
 
Borek said:
You don't need mass, number of moles is enough. But actually you don't need it either, as in the end it should cancel out, and you should be able to express the final result using given information.
Once you know number of moles and gas identity, calculating mass is trivial. What is molar mass of helium?
Okay so,
n= mass/4
then using n/V=P/RT
(m/4)/V=10^5/8.31x298
(m/4)/V=40.3815
Where V is the the volume of N
and when the gas expands into M, its volume is 4V of n
So,
(m/4)/4V=P/8.31x373
40.3815/4=P/8.31x373
P= 31800 (approx.) which is 3.18 x 10^4 Pa, option (A)
Thank you, the answer matched!
 
SteamKing said:
That's what the gas law is telling you: PV = n RT, or n / V = P / RT
Thanks!
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
3K
Replies
9
Views
4K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 16 ·
Replies
16
Views
4K
Replies
1
Views
3K
Replies
14
Views
3K
  • · Replies 18 ·
Replies
18
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K