Final Pressure in Two-Bulb Apparatus After Valve Opening

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J-Nast
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Consider an apparatus where there are two rigid glass bulbs separated from one another by a valve that is closed initially. Bulb #1 has a pressure of 1.3 atm and a volume of 4.27 L and bulb #2 has a pressure of 6.6 atm and a volume of 7.40L. What is the final pressure (in atm) in the apparatus after the valve is opened so that the gases from each side can mix? Assume that the T remains constant and there is no reaction between gases.

I really have no clue where to start with this one, any help would be wonderful. :wink:
 
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you could do it using partial pressures. how much pressure does the gas on bulb 1 put on the entire system and how much does the gas in bulb 2 put in the system? (basically assume that bulb 2 is empty when opened for the first part and the opposite for the second). The pressures will then add to be the final pressure.