- #1

- 45

- 0

## Homework Statement

A 60.5g piece of lead is at 18.6oC. If 328 cal of heat is added to the lead, what is its final temperature? Do not enter units.

## Homework Equations

I was trying to use 328 as the Q value and solve for delta T

Q=mCdelta T

HOWEVER, this wasn't working.

## The Attempt at a Solution

Could someone please explain to me what equation I need to use and how the 328 cal are used? Thanks.