Final Temp of Water & Zinc: Find the Answer

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To find the final temperature of water and zinc, apply the principle of energy conservation, where the heat lost by zinc equals the heat gained by water. The equation used is mZnCZn(Tf - TZn_initial) + mH2OCH2O(Tf - TH2O_initial) = 0. Substituting the values, the equation simplifies to (10 kg)(388 J/kg·°C)(Tf - 68°C) + (32 kg)(4180 J/kg·°C)(Tf - 14°C) = 0. Solving this will yield the final temperature, which is crucial for understanding thermal equilibrium in the system.
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Homework Statement



A 10 kg piece of zinc at 68◦C is placed in a container of water. The water had a mass of 32 kg and a temperature of 14◦C before the zinc was added. The specific heat of zinc and water are 388 J/kg ·◦C and 4180 J/kg ·◦C. What is the final temperature of water and zinc? Answer in units of ◦ C.

Homework Equations



How do you do this? What formula do I use? TIA
 
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Think about the law of energy conservation. If you assume that the system is insulated from the surroundings, then any heat transferred from the water will be absorbed by the zinc. i.e.:

Energy gained by water = energy lost by zinc

You also know that two objects in contact will eventually reach thermal equilibrium, so that their final temperatures are the same. What final temperature, T, will make the energy transferred by the water and zinc equal?
 
So is it 41 C?
 
mZnCZn(Tf-TZn i) + mH2OCH2O(Tf-TH2O i)=0

When I plug in my numbers:

(10 kg)(388 J/kg C)(Tf-68 C) + (32 kg)(4180 J/kg C)(Tf- 14 C) = 0
3880 J/C (Tf-68 C) + 133760 J/C (Tf- 14 C) = 0

Than?!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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