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What will be the final temperature of 3.00 kg of crushed ice with temperature -3.0 C mixed with 4 liters of water with temperature 10.0 C? We can ignore all the energy exchange with the environment

the weight of the ice = 3 kg

Ice temprature = -3 C

melting energy = 3 kg * 333 000 J / kg = 999000 J

weight of water = 4 kg

specific heat capacity of water = 4.2 Jk / kg K

specific heat capacity of ice = 2200 Jk / kg K

I understand just melting energy, but I do not know how will I find out the final temperature. A solution that I have but do not understand why :

dQ ice = 3 * 2200 * (0 + 3) = 19800 J

dQ water = 4 * 4200 * 10 = 168000 J

Melting energy = 999000 J

End temperature becomes equal to 0. but how can I find it?!

**What I do know and I do:**the weight of the ice = 3 kg

Ice temprature = -3 C

melting energy = 3 kg * 333 000 J / kg = 999000 J

weight of water = 4 kg

specific heat capacity of water = 4.2 Jk / kg K

specific heat capacity of ice = 2200 Jk / kg K

I understand just melting energy, but I do not know how will I find out the final temperature. A solution that I have but do not understand why :

dQ ice = 3 * 2200 * (0 + 3) = 19800 J

dQ water = 4 * 4200 * 10 = 168000 J

Melting energy = 999000 J

End temperature becomes equal to 0. but how can I find it?!

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