For a symmetric matrix B=B' where ' is the transpose.
The Attempt at a Solution
Since we know that for a symmetric matrix,
B = B'
I attempted to substitude that in and tried to solve for D.
DTD-1 = (D-1)'T'D
DT = D-1T'DD
D = D-1T'DDT-1
At this point I am stumped since there are D's on both sides, what am I suppose to do?
Thanks a lot for your help.