Find a nonzero vector u with initial point P(-1.3.-5) such that

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To find a nonzero vector u with initial point P(-1, 3, -5) that aligns with the direction of v = (6, 7, -3), the terminal point Q can be calculated as Q(5, 10, -8). For the opposite direction, the terminal point becomes Q(-7, -4, -2). The calculations confirm that both vectors u are correctly derived based on the given conditions. The method used for determining the vectors is validated as correct. The discussion concludes with a confirmation of the procedure and results.
dola
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Find a nonzero vector u with initial point P(-1.3.-5) such that
(a) u has the same direction as v = (6,7,-3)
(b) u is oppositely directed to v = (6,7,-3)
 
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Welcome to PF!

Hi dola! Welcome to PF! :wink:

Show us what you've tried, and where you're stuck, and then we'll know how to help!

Try (a) first. :smile:
 


dola said:
Find a nonzero vector u with initial point P(-1.3.-5) such that
(a) u has the same direction as v = (6,7,-3)
(b) u is oppositely directed to v = (6,7,-3)

---->
Let, the terminal point of u is Q(x,y,z)
Thus u = vector PQ = (x+1, y-3, z+5)

(a) u will have the same direction as v
so, (x+1, y-3, z+5) = (6,7,-3)

x = 5, y = 10, z = -8

Thus one possible ans might be Q(5,10,-8)

(b) u will have the opposite direction as v
so, (x+1, y-3, z+5) = (-6,-7,3)

x = -7, y = -4, z = -2

Thus one possible ans might be Q(-7, -4, -2)


I am not sure whether the procedure is correct. Waiting for explanation
 
dola said:
… I am not sure whether the procedure is correct. Waiting for explanation

Yup, that's fine … both method and result! :biggrin:
 


Thank you
 
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