Find a value of constant k so a limit to infinity exists

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Homework Help Overview

The discussion revolves around finding a constant value of k such that the limit of the expression (x^3 - 6) / (x^k + 3) exists as x approaches infinity. The subject area involves limits in calculus.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the relationship between the growth rates of the numerator and denominator as x approaches infinity. There are attempts to determine specific values of k and questions about the implications of those values on the limit.

Discussion Status

Some participants have suggested that k could be 3, while others have confirmed that this value works. There is ongoing exploration of how different values of k affect the limit, with some guidance provided on the behavior of the limit for k greater than or less than 3.

Contextual Notes

Participants are discussing the implications of various values of k on the limit's existence, with some noting that multiple values could satisfy the condition of the limit existing.

madgab89
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Find a value of constant "k" so a limit to infinity exists

Homework Statement



Find a value of the constant k such that the limit exists.

Homework Equations



lim x to infinity of

x^3-6/x^k+3

The Attempt at a Solution


I started by setting the equation equal to infinity and attempted to rearrange it but got pretty much nowhere. I also broke it up using limit rules and also ended up nowhere.
 
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Can you guess what a k might be? For the limit to exist the numerator and denominator have to grow at similar rates as x->infinity.
 


So would k be 3? I'm not sure I'm understanding..
 


Yes, k=3 is one value that works. What's the limit in that case? Can you show if k>3 the limit is 0 (so it exists) and if k<3 the limit is infinity (so it doesn't exist)? You were just asked to find 'a value'. There are lots of choices.
 


oh my goodness. i just understood it now..thank you *bangs head on desk* :)
 


so to show that say for k=4 the limit is 0, would I just divided each term top and bottom by x^4?
 


and for k=3 the value of the limit would be 1, correct?
 


madgab89 said:
and for k=3 the value of the limit would be 1, correct?

Right on both counts.
 

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