Find Acceleration of Blocks on Table [SOLVED]

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The discussion focuses on solving for the acceleration of two blocks on a table, with Block A weighing 5 lbs and Block B weighing 6 lbs, and a friction coefficient of 0.3. The user struggles with the relationship between the accelerations of the blocks, initially stating that aa = -2ab, which leads to incorrect results. Another participant clarifies that the correct relationship should be aa = 2ab, emphasizing the need to adjust the signs based on the defined motion of the blocks. The confusion arises from the user’s definition of positive motion, which affects the setup of their equations. The thread ultimately resolves the sign issue to help the user find the correct accelerations.
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[SOLVED] Block on a table

Homework Statement



http://img91.imageshack.us/img91/4285/fudgepq5.th.png

I am having some trouble finding the acceleration of the blocks, can anyone help me?

The weight of B is 6 lbs.
The weight of A is 5 lbs.
The friction coef is .3

Homework Equations


The Attempt at a Solution



1) The positive y-axis goes from left to right
sum of forces in y = (6/32)*ab = 2T - 1.8

2) positive y-axis goes from top to bottom
sum of forces in y = (5/32)*aa = 5-T

I know that aa = -2ab
The way my book derives the relationship between aa and ab is from 'dependent motion' they say that length = sa + 2sb and taking the time derivative twice is 0 = aa + 2ab, the problem is with the way I have my equations setup, when i use aa = -2ab i get the wrong answer, does anyone know how I can fix it so I am using aa = -2ab and getting the correct answer?
I don't see anything wrong with my equations, but i am getting the wrong accelerations. Can anyone help?
 
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sign problems

jesuslovesu said:
I know that aa = -2ab
Not exactly. You've defined both aa and ab to be positive when B moves right and A moves down, so it should be: aa = 2ab.
The way my book derives the relationship between aa and ab is from 'dependent motion' they say that length = sa + 2sb and taking the time derivative twice is 0 = aa + 2ab,
That's fine, but realize that you are defining the position of B to increase to the right, but sb actually decreases when mass B moves to the right. That's why you need to change the sign.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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